Consider the quadratic function f(x) = –2x2 + 4x – 2. Find the y-intercept and the equation of the axis of symmetry.The y-intercept is 2.The equation of the axis of symmetry is x = –1.The y-intercept is 1.The equation of the axis of symmetry is x = –2.The y-intercept is –2.The equation of the axis of symmetry is x = 1.The y-intercept is –1.The equation of the axis of symmetry is x = 2.

Answer:The y-intercept is -2The equation of the axis of symmetry is x = 1 ⇒ 3rd answerStep-by-step explanation:* Lets revise the general form of the quadratic function- The general form of the quadratic function is f(x) = ax² + bx + c,  where a, b , c are constant# a is the coefficient of x²# b is the coefficient of x# c is the y-intercept- The meaning of y-intercept is the graph of the function intersects  the y-axis at point (0 , c)- The axis of symmetry of the function is a vertical line   (parallel to the y-axis) and passing through the vertex of the curve- We can find the vertex (h , k) of the curve from a and b, where  h is the x-coordinate of the vertex and k is the y-coordinate of it# h = -b/a and k = f(h)- The equation of any vertical line is x = constant- The axis of symmetry of the quadratic function passing through   the vertex then its equation is x = h* Now lets solve the problem∵ f(x) = -2x² + 4x - 2∴ a = -2 , b = 4 , c = -2∵ The y-intercept is c∴ The y-intercept is -2∵ h = -b/2a∴ h = -4/2(-2) = -4/-4 = 1∴ The equation of the axis of symmetry is x = 1